The value of \(p(x) = 2x^2 - 8x + 6\) is zero when \(x - 1 = 0\) or \(x - 3 = 0\), i.e., when \(x = 1\) or \(x = 3\). So, the zeroes of \(2x^2 - 8x + 6\) are 1 and 3.