problem 40
Conclude from part $(a)$ that $1729=7 \cdot 13 \cdot 19 ; 294,409=37 \cdot 73 \cdot 109 ; 56,052,361=$ $211 \cdot 421 \cdot 631 ; 118,901,521=271 \cdot 541 \cdot 811 ;$ and $172,947,529=307 \cdot 613 \cdot 919$ are Carmichael numbers.
problem 40